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Next, use the aforementioned lattice points to determine how many atoms of iron you get per unit cell Start by using Avogadro's number to determine the mass of a single atom of iron This means that your goal now will be to find So, the edge length of the unit cell is equal to #"3.56 A"#.Īs you know, the density of a substance is defined as mass per unit of volume. The diagonal of the cell will be equal to one radius from the top-corner atom, two radii from the face atom, and one radius from the lower-corner atom

Notice that you can use Pythagoras' Theorem to express #x# in terms of the diagonal of the cell, #d# Let's say that #r# represents the radius of an iron atom and #x# represents the edge length of the unit cell. To calculate the edge length of the unit cell, you need to focus on one side of the cube. #1/2# of an atom in every face lattice point.#1/8"th"# of an atom in every corner lattice point.one lattice point for every one of the six faces of the unit cell.one lattice point for every one of the eight corners of the unit cell.In order to be able to calculate the edge length of the unit cell, you need to start from the characteristics of a face-centered cubic system.Īs you know, a face-centered cubic system is characterized by a unit cell that has a total of #14# lattice points